Metamath Proof Explorer


Theorem acycgrsubgr

Description: The subgraph of an acyclic graph is also acyclic. (Contributed by BTernaryTau, 23-Oct-2023)

Ref Expression
Assertion acycgrsubgr ( ( 𝐺 ∈ AcyclicGraph ∧ 𝑆 SubGraph 𝐺 ) → 𝑆 ∈ AcyclicGraph )

Proof

Step Hyp Ref Expression
1 subgrcycl ⊢ ( 𝑆 SubGraph 𝐺 → ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 → 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ) )
2 1 anim1d ⊢ ( 𝑆 SubGraph 𝐺 → ( ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
3 2 2eximdv ⊢ ( 𝑆 SubGraph 𝐺 → ( ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
4 3 con3d ⊢ ( 𝑆 SubGraph 𝐺 → ( ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) → ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
5 subgrv ⊢ ( 𝑆 SubGraph 𝐺 → ( 𝑆 ∈ V ∧ 𝐺 ∈ V ) )
6 isacycgr ⊢ ( 𝐺 ∈ V → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
7 5 6 simpl2im ⊢ ( 𝑆 SubGraph 𝐺 → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
8 5 simpld ⊢ ( 𝑆 SubGraph 𝐺 → 𝑆 ∈ V )
9 isacycgr ⊢ ( 𝑆 ∈ V → ( 𝑆 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
10 8 9 syl ⊢ ( 𝑆 SubGraph 𝐺 → ( 𝑆 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑆 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
11 4 7 10 3imtr4d ⊢ ( 𝑆 SubGraph 𝐺 → ( 𝐺 ∈ AcyclicGraph → 𝑆 ∈ AcyclicGraph ) )
12 11 impcom ⊢ ( ( 𝐺 ∈ AcyclicGraph ∧ 𝑆 SubGraph 𝐺 ) → 𝑆 ∈ AcyclicGraph )