Metamath Proof Explorer
Description: Infer the equivalence to a contradiction from a negation, in deduction
form. (Contributed by Giovanni Mascellani, 15-Sep-2017)
|
|
Ref |
Expression |
|
Hypothesis |
bifald.1 |
⊢ ( 𝜑 → ¬ 𝜓 ) |
|
Assertion |
bifald |
⊢ ( 𝜑 → ( 𝜓 ↔ ⊥ ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
bifald.1 |
⊢ ( 𝜑 → ¬ 𝜓 ) |
2 |
|
id |
⊢ ( 𝜓 → 𝜓 ) |
3 |
|
falim |
⊢ ( ⊥ → 𝜓 ) |
4 |
2 3
|
pm5.21ni |
⊢ ( ¬ 𝜓 → ( 𝜓 ↔ ⊥ ) ) |
5 |
1 4
|
syl |
⊢ ( 𝜑 → ( 𝜓 ↔ ⊥ ) ) |