Metamath Proof Explorer


Theorem brfullfun

Description: A binary relation form condition for the full function. (Contributed by Scott Fenton, 17-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Hypotheses brfullfun.1 ⊢ 𝐴 ∈ V
brfullfun.2 ⊢ 𝐵 ∈ V
Assertion brfullfun ( 𝐴 FullFun 𝐹 𝐵 ↔ 𝐵 = ( 𝐹 ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 brfullfun.1 ⊢ 𝐴 ∈ V
2 brfullfun.2 ⊢ 𝐵 ∈ V
3 eqcom ⊢ ( ( FullFun 𝐹 ‘ 𝐴 ) = 𝐵 ↔ 𝐵 = ( FullFun 𝐹 ‘ 𝐴 ) )
4 fullfunfnv ⊢ FullFun 𝐹 Fn V
5 fnbrfvb ⊢ ( ( FullFun 𝐹 Fn V ∧ 𝐴 ∈ V ) → ( ( FullFun 𝐹 ‘ 𝐴 ) = 𝐵 ↔ 𝐴 FullFun 𝐹 𝐵 ) )
6 4 1 5 mp2an ⊢ ( ( FullFun 𝐹 ‘ 𝐴 ) = 𝐵 ↔ 𝐴 FullFun 𝐹 𝐵 )
7 fullfunfv ⊢ ( FullFun 𝐹 ‘ 𝐴 ) = ( 𝐹 ‘ 𝐴 )
8 7 eqeq2i ⊢ ( 𝐵 = ( FullFun 𝐹 ‘ 𝐴 ) ↔ 𝐵 = ( 𝐹 ‘ 𝐴 ) )
9 3 6 8 3bitr3i ⊢ ( 𝐴 FullFun 𝐹 𝐵 ↔ 𝐵 = ( 𝐹 ‘ 𝐴 ) )