Metamath Proof Explorer


Theorem brfullfun

Description: A binary relation form condition for the full function. (Contributed by Scott Fenton, 17-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Hypotheses brfullfun.1 𝐴 ∈ V
brfullfun.2 𝐵 ∈ V
Assertion brfullfun ( 𝐴 FullFun 𝐹 𝐵𝐵 = ( 𝐹𝐴 ) )

Proof

Step Hyp Ref Expression
1 brfullfun.1 𝐴 ∈ V
2 brfullfun.2 𝐵 ∈ V
3 eqcom ( ( FullFun 𝐹𝐴 ) = 𝐵𝐵 = ( FullFun 𝐹𝐴 ) )
4 fullfunfnv FullFun 𝐹 Fn V
5 fnbrfvb ( ( FullFun 𝐹 Fn V ∧ 𝐴 ∈ V ) → ( ( FullFun 𝐹𝐴 ) = 𝐵𝐴 FullFun 𝐹 𝐵 ) )
6 4 1 5 mp2an ( ( FullFun 𝐹𝐴 ) = 𝐵𝐴 FullFun 𝐹 𝐵 )
7 fullfunfv ( FullFun 𝐹𝐴 ) = ( 𝐹𝐴 )
8 7 eqeq2i ( 𝐵 = ( FullFun 𝐹𝐴 ) ↔ 𝐵 = ( 𝐹𝐴 ) )
9 3 6 8 3bitr3i ( 𝐴 FullFun 𝐹 𝐵𝐵 = ( 𝐹𝐴 ) )