Metamath Proof Explorer


Theorem cbvmptdavw2

Description: Change bound variable and domain in a maps-to function. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypotheses cbvmptdavw2.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐶 = 𝐷 )
cbvmptdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐴 = 𝐵 )
Assertion cbvmptdavw2 ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) = ( 𝑦 ∈ 𝐵 ↦ 𝐷 ) )

Proof

Step Hyp Ref Expression
1 cbvmptdavw2.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐶 = 𝐷 )
2 cbvmptdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐴 = 𝐵 )
3 eleq1w ⊢ ( 𝑥 = 𝑦 → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐴 ) )
4 3 adantl ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐴 ) )
5 2 eleq2d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑦 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
6 4 5 bitrd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
7 1 eqeq2d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑡 = 𝐶 ↔ 𝑡 = 𝐷 ) )
8 6 7 anbi12d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( ( 𝑥 ∈ 𝐴 ∧ 𝑡 = 𝐶 ) ↔ ( 𝑦 ∈ 𝐵 ∧ 𝑡 = 𝐷 ) ) )
9 8 cbvopab1davw ⊢ ( 𝜑 → { ⟨ 𝑥 , 𝑡 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑡 = 𝐶 ) } = { ⟨ 𝑦 , 𝑡 ⟩ ∣ ( 𝑦 ∈ 𝐵 ∧ 𝑡 = 𝐷 ) } )
10 df-mpt ⊢ ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) = { ⟨ 𝑥 , 𝑡 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑡 = 𝐶 ) }
11 df-mpt ⊢ ( 𝑦 ∈ 𝐵 ↦ 𝐷 ) = { ⟨ 𝑦 , 𝑡 ⟩ ∣ ( 𝑦 ∈ 𝐵 ∧ 𝑡 = 𝐷 ) }
12 9 10 11 3eqtr4g ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) = ( 𝑦 ∈ 𝐵 ↦ 𝐷 ) )