Metamath Proof Explorer


Theorem cbvsbdavw2

Description: Change bound variable in proper substitution. General version of cbvsbdavw . Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypotheses cbvsbdavw2.1 ( 𝜑𝑧 = 𝑤 )
cbvsbdavw2.2 ( ( 𝜑𝑥 = 𝑦 ) → ( 𝜓𝜒 ) )
Assertion cbvsbdavw2 ( 𝜑 → ( [ 𝑧 / 𝑥 ] 𝜓 ↔ [ 𝑤 / 𝑦 ] 𝜒 ) )

Proof

Step Hyp Ref Expression
1 cbvsbdavw2.1 ( 𝜑𝑧 = 𝑤 )
2 cbvsbdavw2.2 ( ( 𝜑𝑥 = 𝑦 ) → ( 𝜓𝜒 ) )
3 equequ2 ( 𝑧 = 𝑤 → ( 𝑡 = 𝑧𝑡 = 𝑤 ) )
4 1 3 syl ( 𝜑 → ( 𝑡 = 𝑧𝑡 = 𝑤 ) )
5 equequ1 ( 𝑥 = 𝑦 → ( 𝑥 = 𝑡𝑦 = 𝑡 ) )
6 5 adantl ( ( 𝜑𝑥 = 𝑦 ) → ( 𝑥 = 𝑡𝑦 = 𝑡 ) )
7 6 2 imbi12d ( ( 𝜑𝑥 = 𝑦 ) → ( ( 𝑥 = 𝑡𝜓 ) ↔ ( 𝑦 = 𝑡𝜒 ) ) )
8 7 cbvaldvaw ( 𝜑 → ( ∀ 𝑥 ( 𝑥 = 𝑡𝜓 ) ↔ ∀ 𝑦 ( 𝑦 = 𝑡𝜒 ) ) )
9 4 8 imbi12d ( 𝜑 → ( ( 𝑡 = 𝑧 → ∀ 𝑥 ( 𝑥 = 𝑡𝜓 ) ) ↔ ( 𝑡 = 𝑤 → ∀ 𝑦 ( 𝑦 = 𝑡𝜒 ) ) ) )
10 9 albidv ( 𝜑 → ( ∀ 𝑡 ( 𝑡 = 𝑧 → ∀ 𝑥 ( 𝑥 = 𝑡𝜓 ) ) ↔ ∀ 𝑡 ( 𝑡 = 𝑤 → ∀ 𝑦 ( 𝑦 = 𝑡𝜒 ) ) ) )
11 df-sb ( [ 𝑧 / 𝑥 ] 𝜓 ↔ ∀ 𝑡 ( 𝑡 = 𝑧 → ∀ 𝑥 ( 𝑥 = 𝑡𝜓 ) ) )
12 df-sb ( [ 𝑤 / 𝑦 ] 𝜒 ↔ ∀ 𝑡 ( 𝑡 = 𝑤 → ∀ 𝑦 ( 𝑦 = 𝑡𝜒 ) ) )
13 10 11 12 3bitr4g ( 𝜑 → ( [ 𝑧 / 𝑥 ] 𝜓 ↔ [ 𝑤 / 𝑦 ] 𝜒 ) )