Metamath Proof Explorer


Theorem chm0

Description: Meet with Hilbert lattice zero. (Contributed by NM, 14-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion chm0 ( 𝐴 ∈ Cℋ → ( 𝐴 ∩ 0ℋ ) = 0ℋ )

Proof

Step Hyp Ref Expression
1 ineq1 ⊢ ( 𝐴 = if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) → ( 𝐴 ∩ 0ℋ ) = ( if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) ∩ 0ℋ ) )
2 1 eqeq1d ⊢ ( 𝐴 = if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) → ( ( 𝐴 ∩ 0ℋ ) = 0ℋ ↔ ( if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) ∩ 0ℋ ) = 0ℋ ) )
3 h0elch ⊢ 0ℋ ∈ Cℋ
4 3 elimel ⊢ if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) ∈ Cℋ
5 4 chm0i ⊢ ( if ( 𝐴 ∈ Cℋ , 𝐴 , 0ℋ ) ∩ 0ℋ ) = 0ℋ
6 2 5 dedth ⊢ ( 𝐴 ∈ Cℋ → ( 𝐴 ∩ 0ℋ ) = 0ℋ )