Metamath Proof Explorer


Theorem congneg

Description: If two integers are congruent mod A , so are their negatives. (Contributed by Stefan O'Rear, 1-Oct-2014)

Ref Expression
Assertion congneg ( ( ( 𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ) ∧ ( 𝐶 ∈ ℤ ∧ 𝐴 ∥ ( 𝐵 − 𝐶 ) ) ) → 𝐴 ∥ ( - 𝐵 − - 𝐶 ) )

Proof

Step Hyp Ref Expression
1 congsym ⊢ ( ( ( 𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ) ∧ ( 𝐶 ∈ ℤ ∧ 𝐴 ∥ ( 𝐵 − 𝐶 ) ) ) → 𝐴 ∥ ( 𝐶 − 𝐵 ) )
2 zcn ⊢ ( 𝐵 ∈ ℤ → 𝐵 ∈ ℂ )
3 zcn ⊢ ( 𝐶 ∈ ℤ → 𝐶 ∈ ℂ )
4 neg2sub ⊢ ( ( 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ ) → ( - 𝐵 − - 𝐶 ) = ( 𝐶 − 𝐵 ) )
5 2 3 4 syl2an ⊢ ( ( 𝐵 ∈ ℤ ∧ 𝐶 ∈ ℤ ) → ( - 𝐵 − - 𝐶 ) = ( 𝐶 − 𝐵 ) )
6 5 ad2ant2lr ⊢ ( ( ( 𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ) ∧ ( 𝐶 ∈ ℤ ∧ 𝐴 ∥ ( 𝐵 − 𝐶 ) ) ) → ( - 𝐵 − - 𝐶 ) = ( 𝐶 − 𝐵 ) )
7 1 6 breqtrrd ⊢ ( ( ( 𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ) ∧ ( 𝐶 ∈ ℤ ∧ 𝐴 ∥ ( 𝐵 − 𝐶 ) ) ) → 𝐴 ∥ ( - 𝐵 − - 𝐶 ) )