Metamath Proof Explorer


Theorem conrel1d

Description: Deduction about composition with a class with no relational content. (Contributed by RP, 24-Dec-2019)

Ref Expression
Hypothesis conrel1d.a ( 𝜑 𝐴 = ∅ )
Assertion conrel1d ( 𝜑 → ( 𝐴𝐵 ) = ∅ )

Proof

Step Hyp Ref Expression
1 conrel1d.a ( 𝜑 𝐴 = ∅ )
2 incom ( dom 𝐴 ∩ ran 𝐵 ) = ( ran 𝐵 ∩ dom 𝐴 )
3 dfdm4 dom 𝐴 = ran 𝐴
4 1 rneqd ( 𝜑 → ran 𝐴 = ran ∅ )
5 rn0 ran ∅ = ∅
6 4 5 eqtrdi ( 𝜑 → ran 𝐴 = ∅ )
7 3 6 syl5eq ( 𝜑 → dom 𝐴 = ∅ )
8 ineq2 ( dom 𝐴 = ∅ → ( ran 𝐵 ∩ dom 𝐴 ) = ( ran 𝐵 ∩ ∅ ) )
9 in0 ( ran 𝐵 ∩ ∅ ) = ∅
10 8 9 eqtrdi ( dom 𝐴 = ∅ → ( ran 𝐵 ∩ dom 𝐴 ) = ∅ )
11 7 10 syl ( 𝜑 → ( ran 𝐵 ∩ dom 𝐴 ) = ∅ )
12 2 11 syl5eq ( 𝜑 → ( dom 𝐴 ∩ ran 𝐵 ) = ∅ )
13 12 coemptyd ( 𝜑 → ( 𝐴𝐵 ) = ∅ )