Metamath Proof Explorer


Theorem conrel1d

Description: Deduction about composition with a class with no relational content. (Contributed by RP, 24-Dec-2019)

Ref Expression
Hypothesis conrel1d.a
|- ( ph -> `' A = (/) )
Assertion conrel1d
|- ( ph -> ( A o. B ) = (/) )

Proof

Step Hyp Ref Expression
1 conrel1d.a
 |-  ( ph -> `' A = (/) )
2 incom
 |-  ( dom A i^i ran B ) = ( ran B i^i dom A )
3 dfdm4
 |-  dom A = ran `' A
4 1 rneqd
 |-  ( ph -> ran `' A = ran (/) )
5 rn0
 |-  ran (/) = (/)
6 4 5 eqtrdi
 |-  ( ph -> ran `' A = (/) )
7 3 6 syl5eq
 |-  ( ph -> dom A = (/) )
8 ineq2
 |-  ( dom A = (/) -> ( ran B i^i dom A ) = ( ran B i^i (/) ) )
9 in0
 |-  ( ran B i^i (/) ) = (/)
10 8 9 eqtrdi
 |-  ( dom A = (/) -> ( ran B i^i dom A ) = (/) )
11 7 10 syl
 |-  ( ph -> ( ran B i^i dom A ) = (/) )
12 2 11 syl5eq
 |-  ( ph -> ( dom A i^i ran B ) = (/) )
13 12 coemptyd
 |-  ( ph -> ( A o. B ) = (/) )