Metamath Proof Explorer
Description: A proof by contradiction, in deduction form. (Contributed by Giovanni
Mascellani, 19-Mar-2018)
|
|
Ref |
Expression |
|
Hypotheses |
contrd.1 |
⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
|
|
contrd.2 |
⊢ ( 𝜑 → ( ¬ 𝜓 → ¬ 𝜒 ) ) |
|
Assertion |
contrd |
⊢ ( 𝜑 → 𝜓 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
contrd.1 |
⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
2 |
|
contrd.2 |
⊢ ( 𝜑 → ( ¬ 𝜓 → ¬ 𝜒 ) ) |
3 |
1 2
|
jcad |
⊢ ( 𝜑 → ( ¬ 𝜓 → ( 𝜒 ∧ ¬ 𝜒 ) ) ) |
4 |
|
pm2.24 |
⊢ ( 𝜒 → ( ¬ 𝜒 → 𝜓 ) ) |
5 |
4
|
imp |
⊢ ( ( 𝜒 ∧ ¬ 𝜒 ) → 𝜓 ) |
6 |
5
|
imim2i |
⊢ ( ( ¬ 𝜓 → ( 𝜒 ∧ ¬ 𝜒 ) ) → ( ¬ 𝜓 → 𝜓 ) ) |
7 |
6
|
pm2.18d |
⊢ ( ( ¬ 𝜓 → ( 𝜒 ∧ ¬ 𝜒 ) ) → 𝜓 ) |
8 |
3 7
|
syl |
⊢ ( 𝜑 → 𝜓 ) |