Metamath Proof Explorer


Theorem coshneg

Description: The cosh function is even. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Assertion coshneg ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cosh ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 negcl ⊢ ( 𝐴 ∈ ℂ → - 𝐴 ∈ ℂ )
2 coshval-named ⊢ ( - 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cos ‘ ( i · - 𝐴 ) ) )
3 1 2 syl ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cos ‘ ( i · - 𝐴 ) ) )
4 ax-icn ⊢ i ∈ ℂ
5 mulcl ⊢ ( ( i ∈ ℂ ∧ - 𝐴 ∈ ℂ ) → ( i · - 𝐴 ) ∈ ℂ )
6 4 1 5 sylancr ⊢ ( 𝐴 ∈ ℂ → ( i · - 𝐴 ) ∈ ℂ )
7 cosneg ⊢ ( ( i · - 𝐴 ) ∈ ℂ → ( cos ‘ - ( i · - 𝐴 ) ) = ( cos ‘ ( i · - 𝐴 ) ) )
8 6 7 syl ⊢ ( 𝐴 ∈ ℂ → ( cos ‘ - ( i · - 𝐴 ) ) = ( cos ‘ ( i · - 𝐴 ) ) )
9 3 8 eqtr4d ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cos ‘ - ( i · - 𝐴 ) ) )
10 4 a1i ⊢ ( 𝐴 ∈ ℂ → i ∈ ℂ )
11 id ⊢ ( 𝐴 ∈ ℂ → 𝐴 ∈ ℂ )
12 10 11 mulneg2d ⊢ ( 𝐴 ∈ ℂ → ( i · - 𝐴 ) = - ( i · 𝐴 ) )
13 12 negeqd ⊢ ( 𝐴 ∈ ℂ → - ( i · - 𝐴 ) = - - ( i · 𝐴 ) )
14 10 11 mulcld ⊢ ( 𝐴 ∈ ℂ → ( i · 𝐴 ) ∈ ℂ )
15 14 negnegd ⊢ ( 𝐴 ∈ ℂ → - - ( i · 𝐴 ) = ( i · 𝐴 ) )
16 13 15 eqtrd ⊢ ( 𝐴 ∈ ℂ → - ( i · - 𝐴 ) = ( i · 𝐴 ) )
17 16 fveq2d ⊢ ( 𝐴 ∈ ℂ → ( cos ‘ - ( i · - 𝐴 ) ) = ( cos ‘ ( i · 𝐴 ) ) )
18 9 17 eqtrd ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cos ‘ ( i · 𝐴 ) ) )
19 coshval-named ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ 𝐴 ) = ( cos ‘ ( i · 𝐴 ) ) )
20 18 19 eqtr4d ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ - 𝐴 ) = ( cosh ‘ 𝐴 ) )