Metamath Proof Explorer


Theorem cplem2

Description: Lemma for the Collection Principle cp . (Contributed by NM, 17-Oct-2003) Use the Scott operation. (Revised by BTernaryTau, 19-Jul-2026)

Ref Expression
Hypothesis cplem2.1 ⊢ 𝐴 ∈ V
Assertion cplem2 ∃ 𝑦 ∀ 𝑥 ∈ 𝐴 ( 𝐵 ≠ ∅ → ( 𝐵 ∩ 𝑦 ) ≠ ∅ )

Proof

Step Hyp Ref Expression
1 cplem2.1 ⊢ 𝐴 ∈ V
2 scottex ⊢ Scott 𝐵 ∈ V
3 1 2 iunex ⊢ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ∈ V
4 nfiu1 ⊢ Ⅎ 𝑥 ∪ 𝑥 ∈ 𝐴 Scott 𝐵
5 4 nfeq2 ⊢ Ⅎ 𝑥 𝑦 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵
6 ineq2 ⊢ ( 𝑦 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵 → ( 𝐵 ∩ 𝑦 ) = ( 𝐵 ∩ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ) )
7 6 neeq1d ⊢ ( 𝑦 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵 → ( ( 𝐵 ∩ 𝑦 ) ≠ ∅ ↔ ( 𝐵 ∩ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ) ≠ ∅ ) )
8 7 imbi2d ⊢ ( 𝑦 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵 → ( ( 𝐵 ≠ ∅ → ( 𝐵 ∩ 𝑦 ) ≠ ∅ ) ↔ ( 𝐵 ≠ ∅ → ( 𝐵 ∩ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ) ≠ ∅ ) ) )
9 5 8 ralbid ⊢ ( 𝑦 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵 → ( ∀ 𝑥 ∈ 𝐴 ( 𝐵 ≠ ∅ → ( 𝐵 ∩ 𝑦 ) ≠ ∅ ) ↔ ∀ 𝑥 ∈ 𝐴 ( 𝐵 ≠ ∅ → ( 𝐵 ∩ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ) ≠ ∅ ) ) )
10 eqid ⊢ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 = ∪ 𝑥 ∈ 𝐴 Scott 𝐵
11 10 cplem1 ⊢ ∀ 𝑥 ∈ 𝐴 ( 𝐵 ≠ ∅ → ( 𝐵 ∩ ∪ 𝑥 ∈ 𝐴 Scott 𝐵 ) ≠ ∅ )
12 3 9 11 ceqsexv2d ⊢ ∃ 𝑦 ∀ 𝑥 ∈ 𝐴 ( 𝐵 ≠ ∅ → ( 𝐵 ∩ 𝑦 ) ≠ ∅ )