Metamath Proof Explorer


Theorem curry1f

Description: Functionality of a curried function with a constant first argument. (Contributed by NM, 29-Mar-2008)

Ref Expression
Hypothesis curry1.1 ⊢ 𝐺 = ( 𝐹 ∘ ◡ ( 2nd ↾ ( { 𝐶 } × V ) ) )
Assertion curry1f ( ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 ∧ 𝐶 ∈ 𝐴 ) → 𝐺 : 𝐵 ⟶ 𝐷 )

Proof

Step Hyp Ref Expression
1 curry1.1 ⊢ 𝐺 = ( 𝐹 ∘ ◡ ( 2nd ↾ ( { 𝐶 } × V ) ) )
2 ffn ⊢ ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 → 𝐹 Fn ( 𝐴 × 𝐵 ) )
3 1 curry1 ⊢ ( ( 𝐹 Fn ( 𝐴 × 𝐵 ) ∧ 𝐶 ∈ 𝐴 ) → 𝐺 = ( 𝑥 ∈ 𝐵 ↦ ( 𝐶 𝐹 𝑥 ) ) )
4 2 3 sylan ⊢ ( ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 ∧ 𝐶 ∈ 𝐴 ) → 𝐺 = ( 𝑥 ∈ 𝐵 ↦ ( 𝐶 𝐹 𝑥 ) ) )
5 fovcdm ⊢ ( ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 ∧ 𝐶 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵 ) → ( 𝐶 𝐹 𝑥 ) ∈ 𝐷 )
6 5 3expa ⊢ ( ( ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 ∧ 𝐶 ∈ 𝐴 ) ∧ 𝑥 ∈ 𝐵 ) → ( 𝐶 𝐹 𝑥 ) ∈ 𝐷 )
7 4 6 fmpt3d ⊢ ( ( 𝐹 : ( 𝐴 × 𝐵 ) ⟶ 𝐷 ∧ 𝐶 ∈ 𝐴 ) → 𝐺 : 𝐵 ⟶ 𝐷 )