Metamath Proof Explorer


Theorem cutminmax

Description: If the left set of X has a maximum and the right set of X has a minimum, then X is equal to the cut of the maximum and the minimum. (Contributed by Scott Fenton, 23-Feb-2026)

Ref Expression
Hypotheses cutminmax.1 ⊢ ( 𝜑 → 𝐿 ∈ ( L ‘ 𝑋 ) )
cutminmax.2 ⊢ ( 𝜑 → ∀ 𝑥 ∈ ( L ‘ 𝑋 ) 𝑥 ≤s 𝐿 )
cutminmax.3 ⊢ ( 𝜑 → 𝑅 ∈ ( R ‘ 𝑋 ) )
cutminmax.4 ⊢ ( 𝜑 → ∀ 𝑦 ∈ ( R ‘ 𝑋 ) 𝑅 ≤s 𝑦 )
Assertion cutminmax ( 𝜑 → 𝑋 = ( { 𝐿 } |s { 𝑅 } ) )

Proof

Step Hyp Ref Expression
1 cutminmax.1 ⊢ ( 𝜑 → 𝐿 ∈ ( L ‘ 𝑋 ) )
2 cutminmax.2 ⊢ ( 𝜑 → ∀ 𝑥 ∈ ( L ‘ 𝑋 ) 𝑥 ≤s 𝐿 )
3 cutminmax.3 ⊢ ( 𝜑 → 𝑅 ∈ ( R ‘ 𝑋 ) )
4 cutminmax.4 ⊢ ( 𝜑 → ∀ 𝑦 ∈ ( R ‘ 𝑋 ) 𝑅 ≤s 𝑦 )
5 lltr ⊢ ( L ‘ 𝑋 ) <<s ( R ‘ 𝑋 )
6 5 a1i ⊢ ( 𝜑 → ( L ‘ 𝑋 ) <<s ( R ‘ 𝑋 ) )
7 breq2 ⊢ ( 𝑦 = 𝑏 → ( 𝑅 ≤s 𝑦 ↔ 𝑅 ≤s 𝑏 ) )
8 7 cbvralvw ⊢ ( ∀ 𝑦 ∈ ( R ‘ 𝑋 ) 𝑅 ≤s 𝑦 ↔ ∀ 𝑏 ∈ ( R ‘ 𝑋 ) 𝑅 ≤s 𝑏 )
9 4 8 sylib ⊢ ( 𝜑 → ∀ 𝑏 ∈ ( R ‘ 𝑋 ) 𝑅 ≤s 𝑏 )
10 6 3 9 cutmin ⊢ ( 𝜑 → ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) = ( ( L ‘ 𝑋 ) |s { 𝑅 } ) )
11 elfvdm ⊢ ( 𝐿 ∈ ( L ‘ 𝑋 ) → 𝑋 ∈ dom L )
12 1 11 syl ⊢ ( 𝜑 → 𝑋 ∈ dom L )
13 leftf ⊢ L : No ⟶ 𝒫 No
14 13 fdmi ⊢ dom L = No
15 12 14 eleqtrdi ⊢ ( 𝜑 → 𝑋 ∈ No )
16 lrcut ⊢ ( 𝑋 ∈ No → ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) = 𝑋 )
17 15 16 syl ⊢ ( 𝜑 → ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) = 𝑋 )
18 3 snssd ⊢ ( 𝜑 → { 𝑅 } ⊆ ( R ‘ 𝑋 ) )
19 ssslts2 ⊢ ( ( ( L ‘ 𝑋 ) <<s ( R ‘ 𝑋 ) ∧ { 𝑅 } ⊆ ( R ‘ 𝑋 ) ) → ( L ‘ 𝑋 ) <<s { 𝑅 } )
20 5 18 19 sylancr ⊢ ( 𝜑 → ( L ‘ 𝑋 ) <<s { 𝑅 } )
21 breq1 ⊢ ( 𝑥 = 𝑎 → ( 𝑥 ≤s 𝐿 ↔ 𝑎 ≤s 𝐿 ) )
22 21 cbvralvw ⊢ ( ∀ 𝑥 ∈ ( L ‘ 𝑋 ) 𝑥 ≤s 𝐿 ↔ ∀ 𝑎 ∈ ( L ‘ 𝑋 ) 𝑎 ≤s 𝐿 )
23 2 22 sylib ⊢ ( 𝜑 → ∀ 𝑎 ∈ ( L ‘ 𝑋 ) 𝑎 ≤s 𝐿 )
24 20 1 23 cutmax ⊢ ( 𝜑 → ( ( L ‘ 𝑋 ) |s { 𝑅 } ) = ( { 𝐿 } |s { 𝑅 } ) )
25 10 17 24 3eqtr3d ⊢ ( 𝜑 → 𝑋 = ( { 𝐿 } |s { 𝑅 } ) )