Metamath Proof Explorer


Theorem cutmax

Description: If A has a maximum, then the maximum may be used alone in the cut. (Contributed by Scott Fenton, 20-Aug-2025)

Ref Expression
Hypotheses cutmax.1 ⊢ ( 𝜑 → 𝐴 <<s 𝐵 )
cutmax.2 ⊢ ( 𝜑 → 𝑋 ∈ 𝐴 )
cutmax.3 ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝐴 𝑦 ≤s 𝑋 )
Assertion cutmax ( 𝜑 → ( 𝐴 |s 𝐵 ) = ( { 𝑋 } |s 𝐵 ) )

Proof

Step Hyp Ref Expression
1 cutmax.1 ⊢ ( 𝜑 → 𝐴 <<s 𝐵 )
2 cutmax.2 ⊢ ( 𝜑 → 𝑋 ∈ 𝐴 )
3 cutmax.3 ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝐴 𝑦 ≤s 𝑋 )
4 breq2 ⊢ ( 𝑥 = 𝑋 → ( 𝑦 ≤s 𝑥 ↔ 𝑦 ≤s 𝑋 ) )
5 4 rexsng ⊢ ( 𝑋 ∈ 𝐴 → ( ∃ 𝑥 ∈ { 𝑋 } 𝑦 ≤s 𝑥 ↔ 𝑦 ≤s 𝑋 ) )
6 2 5 syl ⊢ ( 𝜑 → ( ∃ 𝑥 ∈ { 𝑋 } 𝑦 ≤s 𝑥 ↔ 𝑦 ≤s 𝑋 ) )
7 6 ralbidv ⊢ ( 𝜑 → ( ∀ 𝑦 ∈ 𝐴 ∃ 𝑥 ∈ { 𝑋 } 𝑦 ≤s 𝑥 ↔ ∀ 𝑦 ∈ 𝐴 𝑦 ≤s 𝑋 ) )
8 3 7 mpbird ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝐴 ∃ 𝑥 ∈ { 𝑋 } 𝑦 ≤s 𝑥 )
9 simpr ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → 𝑥 ∈ 𝐵 )
10 sltsss2 ⊢ ( 𝐴 <<s 𝐵 → 𝐵 ⊆ No )
11 1 10 syl ⊢ ( 𝜑 → 𝐵 ⊆ No )
12 11 sselda ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → 𝑥 ∈ No )
13 lesid ⊢ ( 𝑥 ∈ No → 𝑥 ≤s 𝑥 )
14 12 13 syl ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → 𝑥 ≤s 𝑥 )
15 breq1 ⊢ ( 𝑦 = 𝑥 → ( 𝑦 ≤s 𝑥 ↔ 𝑥 ≤s 𝑥 ) )
16 15 rspcev ⊢ ( ( 𝑥 ∈ 𝐵 ∧ 𝑥 ≤s 𝑥 ) → ∃ 𝑦 ∈ 𝐵 𝑦 ≤s 𝑥 )
17 9 14 16 syl2anc ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → ∃ 𝑦 ∈ 𝐵 𝑦 ≤s 𝑥 )
18 17 ralrimiva ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐵 ∃ 𝑦 ∈ 𝐵 𝑦 ≤s 𝑥 )
19 cutcuts ⊢ ( 𝐴 <<s 𝐵 → ( ( 𝐴 |s 𝐵 ) ∈ No ∧ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) )
20 1 19 syl ⊢ ( 𝜑 → ( ( 𝐴 |s 𝐵 ) ∈ No ∧ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) )
21 20 simp2d ⊢ ( 𝜑 → 𝐴 <<s { ( 𝐴 |s 𝐵 ) } )
22 2 snssd ⊢ ( 𝜑 → { 𝑋 } ⊆ 𝐴 )
23 ssslts1 ⊢ ( ( 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { 𝑋 } ⊆ 𝐴 ) → { 𝑋 } <<s { ( 𝐴 |s 𝐵 ) } )
24 21 22 23 syl2anc ⊢ ( 𝜑 → { 𝑋 } <<s { ( 𝐴 |s 𝐵 ) } )
25 20 simp3d ⊢ ( 𝜑 → { ( 𝐴 |s 𝐵 ) } <<s 𝐵 )
26 1 8 18 24 25 cofcut1d ⊢ ( 𝜑 → ( 𝐴 |s 𝐵 ) = ( { 𝑋 } |s 𝐵 ) )