Metamath Proof Explorer


Theorem dihss

Description: The value of isomorphism H is a set of vectors. (Contributed by NM, 14-Mar-2014)

Ref Expression
Hypotheses dihss.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
dihss.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
dihss.i ⊢ 𝐼 = ( ( DIsoH ‘ 𝐾 ) ‘ 𝑊 )
dihss.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
dihss.v ⊢ 𝑉 = ( Base ‘ 𝑈 )
Assertion dihss ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑋 ∈ 𝐵 ) → ( 𝐼 ‘ 𝑋 ) ⊆ 𝑉 )

Proof

Step Hyp Ref Expression
1 dihss.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 dihss.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
3 dihss.i ⊢ 𝐼 = ( ( DIsoH ‘ 𝐾 ) ‘ 𝑊 )
4 dihss.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
5 dihss.v ⊢ 𝑉 = ( Base ‘ 𝑈 )
6 eqid ⊢ ( LSubSp ‘ 𝑈 ) = ( LSubSp ‘ 𝑈 )
7 1 2 3 4 6 dihlss ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑋 ∈ 𝐵 ) → ( 𝐼 ‘ 𝑋 ) ∈ ( LSubSp ‘ 𝑈 ) )
8 5 6 lssss ⊢ ( ( 𝐼 ‘ 𝑋 ) ∈ ( LSubSp ‘ 𝑈 ) → ( 𝐼 ‘ 𝑋 ) ⊆ 𝑉 )
9 7 8 syl ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑋 ∈ 𝐵 ) → ( 𝐼 ‘ 𝑋 ) ⊆ 𝑉 )