Metamath Proof Explorer


Theorem elsetpreimafveqfv

Description: The elements of the preimage of a function value have the same function values. (Contributed by AV, 5-Mar-2024)

Ref Expression
Hypothesis setpreimafvex.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
Assertion elsetpreimafveqfv ( ( 𝐹 Fn 𝐴 ∧ ( 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ∧ 𝑌 ∈ 𝑆 ) ) → ( 𝐹 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑌 ) )

Proof

Step Hyp Ref Expression
1 setpreimafvex.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
2 1 elsetpreimafvbi ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ) → ( 𝑌 ∈ 𝑆 ↔ ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) ) )
3 simpr ⊢ ( ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) → ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) )
4 3 eqcomd ⊢ ( ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) → ( 𝐹 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑌 ) )
5 2 4 biimtrdi ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ) → ( 𝑌 ∈ 𝑆 → ( 𝐹 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑌 ) ) )
6 5 3exp ⊢ ( 𝐹 Fn 𝐴 → ( 𝑆 ∈ 𝑃 → ( 𝑋 ∈ 𝑆 → ( 𝑌 ∈ 𝑆 → ( 𝐹 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑌 ) ) ) ) )
7 6 3imp2 ⊢ ( ( 𝐹 Fn 𝐴 ∧ ( 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ∧ 𝑌 ∈ 𝑆 ) ) → ( 𝐹 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑌 ) )