Metamath Proof Explorer


Theorem eqfvelsetpreimafv

Description: If an element of the domain of the function has the same function value as an element of the preimage of a function value, then it is an element of the same preimage. (Contributed by AV, 9-Mar-2024)

Ref Expression
Hypothesis setpreimafvex.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
Assertion eqfvelsetpreimafv ( ( 𝐹 Fn 𝐴 ∧ 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ) → ( ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) → 𝑌 ∈ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 setpreimafvex.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
2 1 elsetpreimafvbi ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ) → ( 𝑌 ∈ 𝑆 ↔ ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) ) )
3 2 biimprd ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑆 ∈ 𝑃 ∧ 𝑋 ∈ 𝑆 ) → ( ( 𝑌 ∈ 𝐴 ∧ ( 𝐹 ‘ 𝑌 ) = ( 𝐹 ‘ 𝑋 ) ) → 𝑌 ∈ 𝑆 ) )