Metamath Proof Explorer


Theorem eusn

Description: Two ways to express " A is a singleton". (Contributed by NM, 30-Oct-2010)

Ref Expression
Assertion eusn ( ∃! 𝑥 𝑥 ∈ 𝐴 ↔ ∃ 𝑥 𝐴 = { 𝑥 } )

Proof

Step Hyp Ref Expression
1 euabsn ⊢ ( ∃! 𝑥 𝑥 ∈ 𝐴 ↔ ∃ 𝑥 { 𝑥 ∣ 𝑥 ∈ 𝐴 } = { 𝑥 } )
2 abid2 ⊢ { 𝑥 ∣ 𝑥 ∈ 𝐴 } = 𝐴
3 2 eqeq1i ⊢ ( { 𝑥 ∣ 𝑥 ∈ 𝐴 } = { 𝑥 } ↔ 𝐴 = { 𝑥 } )
4 3 exbii ⊢ ( ∃ 𝑥 { 𝑥 ∣ 𝑥 ∈ 𝐴 } = { 𝑥 } ↔ ∃ 𝑥 𝐴 = { 𝑥 } )
5 1 4 bitri ⊢ ( ∃! 𝑥 𝑥 ∈ 𝐴 ↔ ∃ 𝑥 𝐴 = { 𝑥 } )