Metamath Proof Explorer


Theorem exdifsn

Description: There exists an element in a class excluding a singleton if and only if there exists an element in the original class not equal to the singleton element. (Contributed by BTernaryTau, 15-Sep-2023)

Ref Expression
Assertion exdifsn ( ∃ 𝑥 𝑥 ∈ ( 𝐴 ∖ { 𝐵 } ) ↔ ∃ 𝑥 ∈ 𝐴 𝑥 ≠ 𝐵 )

Proof

Step Hyp Ref Expression
1 eldifsn ⊢ ( 𝑥 ∈ ( 𝐴 ∖ { 𝐵 } ) ↔ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ≠ 𝐵 ) )
2 1 exbii ⊢ ( ∃ 𝑥 𝑥 ∈ ( 𝐴 ∖ { 𝐵 } ) ↔ ∃ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝑥 ≠ 𝐵 ) )
3 df-rex ⊢ ( ∃ 𝑥 ∈ 𝐴 𝑥 ≠ 𝐵 ↔ ∃ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝑥 ≠ 𝐵 ) )
4 2 3 bitr4i ⊢ ( ∃ 𝑥 𝑥 ∈ ( 𝐴 ∖ { 𝐵 } ) ↔ ∃ 𝑥 ∈ 𝐴 𝑥 ≠ 𝐵 )