Metamath Proof Explorer


Theorem srcmpltd

Description: If a statement is true for every element of a class and for every element of its complement relative to a second class, then it is true for every element in the second class. (Contributed by BTernaryTau, 27-Sep-2023)

Ref Expression
Hypotheses srcmpltd.1 ⊢ ( 𝜑 → ( 𝐶 ∈ 𝐴 → 𝜓 ) )
srcmpltd.2 ⊢ ( 𝜑 → ( 𝐶 ∈ ( 𝐵 ∖ 𝐴 ) → 𝜓 ) )
Assertion srcmpltd ( 𝜑 → ( 𝐶 ∈ 𝐵 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 srcmpltd.1 ⊢ ( 𝜑 → ( 𝐶 ∈ 𝐴 → 𝜓 ) )
2 srcmpltd.2 ⊢ ( 𝜑 → ( 𝐶 ∈ ( 𝐵 ∖ 𝐴 ) → 𝜓 ) )
3 elun2 ⊢ ( 𝐶 ∈ 𝐵 → 𝐶 ∈ ( 𝐴 ∪ 𝐵 ) )
4 undif2 ⊢ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) = ( 𝐴 ∪ 𝐵 )
5 3 4 eleqtrrdi ⊢ ( 𝐶 ∈ 𝐵 → 𝐶 ∈ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) )
6 elunant ⊢ ( ( 𝐶 ∈ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) → 𝜓 ) ↔ ( ( 𝐶 ∈ 𝐴 → 𝜓 ) ∧ ( 𝐶 ∈ ( 𝐵 ∖ 𝐴 ) → 𝜓 ) ) )
7 1 2 6 sylanbrc ⊢ ( 𝜑 → ( 𝐶 ∈ ( 𝐴 ∪ ( 𝐵 ∖ 𝐴 ) ) → 𝜓 ) )
8 5 7 syl5 ⊢ ( 𝜑 → ( 𝐶 ∈ 𝐵 → 𝜓 ) )