Metamath Proof Explorer


Theorem exdifsn

Description: There exists an element in a class excluding a singleton if and only if there exists an element in the original class not equal to the singleton element. (Contributed by BTernaryTau, 15-Sep-2023)

Ref Expression
Assertion exdifsn ⊢ ∃ x x ∈ A ∖ B ↔ ∃ x ∈ A x ≠ B

Proof

Step Hyp Ref Expression
1 eldifsn ⊢ x ∈ A ∖ B ↔ x ∈ A ∧ x ≠ B
2 1 exbii ⊢ ∃ x x ∈ A ∖ B ↔ ∃ x x ∈ A ∧ x ≠ B
3 df-rex ⊢ ∃ x ∈ A x ≠ B ↔ ∃ x x ∈ A ∧ x ≠ B
4 2 3 bitr4i ⊢ ∃ x x ∈ A ∖ B ↔ ∃ x ∈ A x ≠ B