Metamath Proof Explorer


Theorem exlimim

Description: Closed form of exlimimd . (Contributed by ML, 17-Jul-2020)

Ref Expression
Assertion exlimim ( ( ∃ 𝑥 𝜑 ∧ ∀ 𝑥 ( 𝜑 → 𝜓 ) ) → 𝜓 )

Proof

Step Hyp Ref Expression
1 nfa1 ⊢ Ⅎ 𝑥 ∀ 𝑥 ( 𝜑 → 𝜓 )
2 nfv ⊢ Ⅎ 𝑥 𝜓
3 sp ⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) → ( 𝜑 → 𝜓 ) )
4 1 2 3 exlimd ⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) → ( ∃ 𝑥 𝜑 → 𝜓 ) )
5 4 impcom ⊢ ( ( ∃ 𝑥 𝜑 ∧ ∀ 𝑥 ( 𝜑 → 𝜓 ) ) → 𝜓 )