Metamath Proof Explorer


Theorem exps1

Description: Surreal exponentiation to one. (Contributed by Scott Fenton, 24-Jul-2025)

Ref Expression
Assertion exps1 ( 𝐴 ∈ No → ( 𝐴 ↑s 1s ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 1nns ⊢ 1s ∈ ℕs
2 expnnsval ⊢ ( ( 𝐴 ∈ No ∧ 1s ∈ ℕs ) → ( 𝐴 ↑s 1s ) = ( seqs 1s ( ·s , ( ℕs × { 𝐴 } ) ) ‘ 1s ) )
3 1 2 mpan2 ⊢ ( 𝐴 ∈ No → ( 𝐴 ↑s 1s ) = ( seqs 1s ( ·s , ( ℕs × { 𝐴 } ) ) ‘ 1s ) )
4 1no ⊢ 1s ∈ No
5 4 a1i ⊢ ( 𝐴 ∈ No → 1s ∈ No )
6 5 seqs1 ⊢ ( 𝐴 ∈ No → ( seqs 1s ( ·s , ( ℕs × { 𝐴 } ) ) ‘ 1s ) = ( ( ℕs × { 𝐴 } ) ‘ 1s ) )
7 fvconst2g ⊢ ( ( 𝐴 ∈ No ∧ 1s ∈ ℕs ) → ( ( ℕs × { 𝐴 } ) ‘ 1s ) = 𝐴 )
8 1 7 mpan2 ⊢ ( 𝐴 ∈ No → ( ( ℕs × { 𝐴 } ) ‘ 1s ) = 𝐴 )
9 3 6 8 3eqtrd ⊢ ( 𝐴 ∈ No → ( 𝐴 ↑s 1s ) = 𝐴 )