Metamath Proof Explorer


Theorem f102g

Description: A function that maps the empty set to a class is injective. (Contributed by Zhi Wang, 1-Oct-2024)

Ref Expression
Assertion f102g ( ( 𝐴 = ∅ ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 : 𝐴 –1-1→ 𝐵 )

Proof

Step Hyp Ref Expression
1 feq2 ⊢ ( 𝐴 = ∅ → ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐹 : ∅ ⟶ 𝐵 ) )
2 1 biimpa ⊢ ( ( 𝐴 = ∅ ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 : ∅ ⟶ 𝐵 )
3 f0bi ⊢ ( 𝐹 : ∅ ⟶ 𝐵 ↔ 𝐹 = ∅ )
4 f10 ⊢ ∅ : ∅ –1-1→ 𝐵
5 f1eq1 ⊢ ( 𝐹 = ∅ → ( 𝐹 : ∅ –1-1→ 𝐵 ↔ ∅ : ∅ –1-1→ 𝐵 ) )
6 4 5 mpbiri ⊢ ( 𝐹 = ∅ → 𝐹 : ∅ –1-1→ 𝐵 )
7 3 6 sylbi ⊢ ( 𝐹 : ∅ ⟶ 𝐵 → 𝐹 : ∅ –1-1→ 𝐵 )
8 2 7 syl ⊢ ( ( 𝐴 = ∅ ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 : ∅ –1-1→ 𝐵 )
9 f1eq2 ⊢ ( 𝐴 = ∅ → ( 𝐹 : 𝐴 –1-1→ 𝐵 ↔ 𝐹 : ∅ –1-1→ 𝐵 ) )
10 9 adantr ⊢ ( ( 𝐴 = ∅ ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → ( 𝐹 : 𝐴 –1-1→ 𝐵 ↔ 𝐹 : ∅ –1-1→ 𝐵 ) )
11 8 10 mpbird ⊢ ( ( 𝐴 = ∅ ∧ 𝐹 : 𝐴 ⟶ 𝐵 ) → 𝐹 : 𝐴 –1-1→ 𝐵 )