Metamath Proof Explorer
Description: Equivalence of function value and ordered pair membership, analogous to
funopfvb . (Contributed by Alexander van der Vekens, 25-May-2017)
|
|
Ref |
Expression |
|
Assertion |
funopafvb |
⊢ ( ( Fun 𝐹 ∧ 𝐴 ∈ dom 𝐹 ) → ( ( 𝐹 ''' 𝐴 ) = 𝐵 ↔ 〈 𝐴 , 𝐵 〉 ∈ 𝐹 ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
funfn |
⊢ ( Fun 𝐹 ↔ 𝐹 Fn dom 𝐹 ) |
| 2 |
|
fnopafvb |
⊢ ( ( 𝐹 Fn dom 𝐹 ∧ 𝐴 ∈ dom 𝐹 ) → ( ( 𝐹 ''' 𝐴 ) = 𝐵 ↔ 〈 𝐴 , 𝐵 〉 ∈ 𝐹 ) ) |
| 3 |
1 2
|
sylanb |
⊢ ( ( Fun 𝐹 ∧ 𝐴 ∈ dom 𝐹 ) → ( ( 𝐹 ''' 𝐴 ) = 𝐵 ↔ 〈 𝐴 , 𝐵 〉 ∈ 𝐹 ) ) |