Metamath Proof Explorer


Theorem gsumsubg

Description: The group sum in a subgroup is the same as the group sum. (Contributed by Thierry Arnoux, 28-May-2023)

Ref Expression
Hypotheses gsumsubg.1 ⊢ 𝐻 = ( 𝐺 ↾s 𝐵 )
gsumsubg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
gsumsubg.f ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
gsumsubg.b ⊢ ( 𝜑 → 𝐵 ∈ ( SubGrp ‘ 𝐺 ) )
Assertion gsumsubg ( 𝜑 → ( 𝐺 Σg 𝐹 ) = ( 𝐻 Σg 𝐹 ) )

Proof

Step Hyp Ref Expression
1 gsumsubg.1 ⊢ 𝐻 = ( 𝐺 ↾s 𝐵 )
2 gsumsubg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
3 gsumsubg.f ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝐵 )
4 gsumsubg.b ⊢ ( 𝜑 → 𝐵 ∈ ( SubGrp ‘ 𝐺 ) )
5 eqid ⊢ ( Base ‘ 𝐺 ) = ( Base ‘ 𝐺 )
6 eqid ⊢ ( +g ‘ 𝐺 ) = ( +g ‘ 𝐺 )
7 4 elfvexd ⊢ ( 𝜑 → 𝐺 ∈ V )
8 5 subgss ⊢ ( 𝐵 ∈ ( SubGrp ‘ 𝐺 ) → 𝐵 ⊆ ( Base ‘ 𝐺 ) )
9 4 8 syl ⊢ ( 𝜑 → 𝐵 ⊆ ( Base ‘ 𝐺 ) )
10 eqid ⊢ ( 0g ‘ 𝐺 ) = ( 0g ‘ 𝐺 )
11 10 subg0cl ⊢ ( 𝐵 ∈ ( SubGrp ‘ 𝐺 ) → ( 0g ‘ 𝐺 ) ∈ 𝐵 )
12 4 11 syl ⊢ ( 𝜑 → ( 0g ‘ 𝐺 ) ∈ 𝐵 )
13 subgrcl ⊢ ( 𝐵 ∈ ( SubGrp ‘ 𝐺 ) → 𝐺 ∈ Grp )
14 4 13 syl ⊢ ( 𝜑 → 𝐺 ∈ Grp )
15 5 6 10 grplid ⊢ ( ( 𝐺 ∈ Grp ∧ 𝑥 ∈ ( Base ‘ 𝐺 ) ) → ( ( 0g ‘ 𝐺 ) ( +g ‘ 𝐺 ) 𝑥 ) = 𝑥 )
16 5 6 10 grprid ⊢ ( ( 𝐺 ∈ Grp ∧ 𝑥 ∈ ( Base ‘ 𝐺 ) ) → ( 𝑥 ( +g ‘ 𝐺 ) ( 0g ‘ 𝐺 ) ) = 𝑥 )
17 15 16 jca ⊢ ( ( 𝐺 ∈ Grp ∧ 𝑥 ∈ ( Base ‘ 𝐺 ) ) → ( ( ( 0g ‘ 𝐺 ) ( +g ‘ 𝐺 ) 𝑥 ) = 𝑥 ∧ ( 𝑥 ( +g ‘ 𝐺 ) ( 0g ‘ 𝐺 ) ) = 𝑥 ) )
18 14 17 sylan ⊢ ( ( 𝜑 ∧ 𝑥 ∈ ( Base ‘ 𝐺 ) ) → ( ( ( 0g ‘ 𝐺 ) ( +g ‘ 𝐺 ) 𝑥 ) = 𝑥 ∧ ( 𝑥 ( +g ‘ 𝐺 ) ( 0g ‘ 𝐺 ) ) = 𝑥 ) )
19 5 6 1 7 2 9 3 12 18 gsumress ⊢ ( 𝜑 → ( 𝐺 Σg 𝐹 ) = ( 𝐻 Σg 𝐹 ) )