Metamath Proof Explorer


Theorem imdistani

Description: Distribution of implication with conjunction. (Contributed by NM, 1-Aug-1994)

Ref Expression
Hypothesis imdistani.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
Assertion imdistani ( ( 𝜑 ∧ 𝜓 ) → ( 𝜑 ∧ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 imdistani.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
2 1 anc2li ⊢ ( 𝜑 → ( 𝜓 → ( 𝜑 ∧ 𝜒 ) ) )
3 2 imp ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜑 ∧ 𝜒 ) )