Metamath Proof Explorer


Theorem inagflat

Description: Any point lies in a flat angle. (Contributed by Thierry Arnoux, 13-Feb-2023)

Ref Expression
Hypotheses isinag.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
isinag.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
isinag.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
isinag.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑃 )
isinag.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
isinag.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
isinag.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
inagflat.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
inagflat.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑃 )
inagflat.1 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
inagflat.2 ⊢ ( 𝜑 → 𝐶 ≠ 𝐵 )
inagflat.3 ⊢ ( 𝜑 → 𝑋 ≠ 𝐵 )
inagflat.4 ⊢ ( 𝜑 → 𝐵 ∈ ( 𝐴 𝐼 𝐶 ) )
Assertion inagflat ( 𝜑 → 𝑋 ( inA ‘ 𝐺 ) ⟨“ 𝐴 𝐵 𝐶 ”⟩ )

Proof

Step Hyp Ref Expression
1 isinag.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 isinag.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 isinag.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
4 isinag.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑃 )
5 isinag.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
6 isinag.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
7 isinag.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
8 inagflat.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
9 inagflat.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑃 )
10 inagflat.1 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
11 inagflat.2 ⊢ ( 𝜑 → 𝐶 ≠ 𝐵 )
12 inagflat.3 ⊢ ( 𝜑 → 𝑋 ≠ 𝐵 )
13 inagflat.4 ⊢ ( 𝜑 → 𝐵 ∈ ( 𝐴 𝐼 𝐶 ) )
14 eqidd ⊢ ( 𝜑 → 𝐵 = 𝐵 )
15 14 orcd ⊢ ( 𝜑 → ( 𝐵 = 𝐵 ∨ 𝐵 ( 𝐾 ‘ 𝐵 ) 𝑋 ) )
16 1 2 3 4 5 6 7 8 6 10 11 12 13 15 isinagd ⊢ ( 𝜑 → 𝑋 ( inA ‘ 𝐺 ) ⟨“ 𝐴 𝐵 𝐶 ”⟩ )