Metamath Proof Explorer


Theorem ineq1

Description: Equality theorem for intersection of two classes. (Contributed by NM, 14-Dec-1993) (Proof shortened by SN, 20-Sep-2023)

Ref Expression
Assertion ineq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )

Proof

Step Hyp Ref Expression
1 rabeq ( 𝐴 = 𝐵 → { 𝑥𝐴𝑥𝐶 } = { 𝑥𝐵𝑥𝐶 } )
2 dfin5 ( 𝐴𝐶 ) = { 𝑥𝐴𝑥𝐶 }
3 dfin5 ( 𝐵𝐶 ) = { 𝑥𝐵𝑥𝐶 }
4 1 2 3 3eqtr4g ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )