Metamath Proof Explorer


Theorem iotaexeu

Description: The iota class exists. This theorem does not require ax-nul for its proof. (Contributed by Andrew Salmon, 11-Jul-2011)

Ref Expression
Assertion iotaexeu ( ∃! 𝑥 𝜑 → ( ℩ 𝑥 𝜑 ) ∈ V )

Proof

Step Hyp Ref Expression
1 iotaval ( ∀ 𝑥 ( 𝜑𝑥 = 𝑦 ) → ( ℩ 𝑥 𝜑 ) = 𝑦 )
2 1 eqcomd ( ∀ 𝑥 ( 𝜑𝑥 = 𝑦 ) → 𝑦 = ( ℩ 𝑥 𝜑 ) )
3 2 eximi ( ∃ 𝑦𝑥 ( 𝜑𝑥 = 𝑦 ) → ∃ 𝑦 𝑦 = ( ℩ 𝑥 𝜑 ) )
4 eu6 ( ∃! 𝑥 𝜑 ↔ ∃ 𝑦𝑥 ( 𝜑𝑥 = 𝑦 ) )
5 isset ( ( ℩ 𝑥 𝜑 ) ∈ V ↔ ∃ 𝑦 𝑦 = ( ℩ 𝑥 𝜑 ) )
6 3 4 5 3imtr4i ( ∃! 𝑥 𝜑 → ( ℩ 𝑥 𝜑 ) ∈ V )