Metamath Proof Explorer


Theorem ispsubclN

Description: The predicate "is a closed projective subspace". (Contributed by NM, 23-Jan-2012) (New usage is discouraged.)

Ref Expression
Hypotheses psubclset.a 𝐴 = ( Atoms ‘ 𝐾 )
psubclset.p = ( ⊥𝑃𝐾 )
psubclset.c 𝐶 = ( PSubCl ‘ 𝐾 )
Assertion ispsubclN ( 𝐾𝐷 → ( 𝑋𝐶 ↔ ( 𝑋𝐴 ∧ ( ‘ ( 𝑋 ) ) = 𝑋 ) ) )

Proof

Step Hyp Ref Expression
1 psubclset.a 𝐴 = ( Atoms ‘ 𝐾 )
2 psubclset.p = ( ⊥𝑃𝐾 )
3 psubclset.c 𝐶 = ( PSubCl ‘ 𝐾 )
4 1 2 3 psubclsetN ( 𝐾𝐷𝐶 = { 𝑥 ∣ ( 𝑥𝐴 ∧ ( ‘ ( 𝑥 ) ) = 𝑥 ) } )
5 4 eleq2d ( 𝐾𝐷 → ( 𝑋𝐶𝑋 ∈ { 𝑥 ∣ ( 𝑥𝐴 ∧ ( ‘ ( 𝑥 ) ) = 𝑥 ) } ) )
6 1 fvexi 𝐴 ∈ V
7 6 ssex ( 𝑋𝐴𝑋 ∈ V )
8 7 adantr ( ( 𝑋𝐴 ∧ ( ‘ ( 𝑋 ) ) = 𝑋 ) → 𝑋 ∈ V )
9 sseq1 ( 𝑥 = 𝑋 → ( 𝑥𝐴𝑋𝐴 ) )
10 2fveq3 ( 𝑥 = 𝑋 → ( ‘ ( 𝑥 ) ) = ( ‘ ( 𝑋 ) ) )
11 id ( 𝑥 = 𝑋𝑥 = 𝑋 )
12 10 11 eqeq12d ( 𝑥 = 𝑋 → ( ( ‘ ( 𝑥 ) ) = 𝑥 ↔ ( ‘ ( 𝑋 ) ) = 𝑋 ) )
13 9 12 anbi12d ( 𝑥 = 𝑋 → ( ( 𝑥𝐴 ∧ ( ‘ ( 𝑥 ) ) = 𝑥 ) ↔ ( 𝑋𝐴 ∧ ( ‘ ( 𝑋 ) ) = 𝑋 ) ) )
14 8 13 elab3 ( 𝑋 ∈ { 𝑥 ∣ ( 𝑥𝐴 ∧ ( ‘ ( 𝑥 ) ) = 𝑥 ) } ↔ ( 𝑋𝐴 ∧ ( ‘ ( 𝑋 ) ) = 𝑋 ) )
15 5 14 bitrdi ( 𝐾𝐷 → ( 𝑋𝐶 ↔ ( 𝑋𝐴 ∧ ( ‘ ( 𝑋 ) ) = 𝑋 ) ) )