Metamath Proof Explorer


Theorem isptfin

Description: The statement "is a point-finite cover." (Contributed by Jeff Hankins, 21-Jan-2010)

Ref Expression
Hypothesis isptfin.1 ⊢ 𝑋 = ∪ 𝐴
Assertion isptfin ( 𝐴 ∈ 𝐵 → ( 𝐴 ∈ PtFin ↔ ∀ 𝑥 ∈ 𝑋 { 𝑦 ∈ 𝐴 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ) )

Proof

Step Hyp Ref Expression
1 isptfin.1 ⊢ 𝑋 = ∪ 𝐴
2 unieq ⊢ ( 𝑎 = 𝐴 → ∪ 𝑎 = ∪ 𝐴 )
3 2 1 eqtr4di ⊢ ( 𝑎 = 𝐴 → ∪ 𝑎 = 𝑋 )
4 rabeq ⊢ ( 𝑎 = 𝐴 → { 𝑦 ∈ 𝑎 ∣ 𝑥 ∈ 𝑦 } = { 𝑦 ∈ 𝐴 ∣ 𝑥 ∈ 𝑦 } )
5 4 eleq1d ⊢ ( 𝑎 = 𝐴 → ( { 𝑦 ∈ 𝑎 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ↔ { 𝑦 ∈ 𝐴 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ) )
6 3 5 raleqbidv ⊢ ( 𝑎 = 𝐴 → ( ∀ 𝑥 ∈ ∪ 𝑎 { 𝑦 ∈ 𝑎 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ↔ ∀ 𝑥 ∈ 𝑋 { 𝑦 ∈ 𝐴 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ) )
7 df-ptfin ⊢ PtFin = { 𝑎 ∣ ∀ 𝑥 ∈ ∪ 𝑎 { 𝑦 ∈ 𝑎 ∣ 𝑥 ∈ 𝑦 } ∈ Fin }
8 6 7 elab2g ⊢ ( 𝐴 ∈ 𝐵 → ( 𝐴 ∈ PtFin ↔ ∀ 𝑥 ∈ 𝑋 { 𝑦 ∈ 𝐴 ∣ 𝑥 ∈ 𝑦 } ∈ Fin ) )