Step |
Hyp |
Ref |
Expression |
1 |
|
fnima |
⊢ ( 𝐹 Fn 𝐴 → ( 𝐹 “ 𝐴 ) = ran 𝐹 ) |
2 |
1
|
sseq1d |
⊢ ( 𝐹 Fn 𝐴 → ( ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ↔ ran 𝐹 ⊆ 𝐶 ) ) |
3 |
2
|
anbi2d |
⊢ ( 𝐹 Fn 𝐴 → ( ( ran 𝐹 ⊆ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ ( ran 𝐹 ⊆ 𝐵 ∧ ran 𝐹 ⊆ 𝐶 ) ) ) |
4 |
|
ssin |
⊢ ( ( ran 𝐹 ⊆ 𝐵 ∧ ran 𝐹 ⊆ 𝐶 ) ↔ ran 𝐹 ⊆ ( 𝐵 ∩ 𝐶 ) ) |
5 |
3 4
|
bitrdi |
⊢ ( 𝐹 Fn 𝐴 → ( ( ran 𝐹 ⊆ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ ran 𝐹 ⊆ ( 𝐵 ∩ 𝐶 ) ) ) |
6 |
5
|
pm5.32i |
⊢ ( ( 𝐹 Fn 𝐴 ∧ ( ran 𝐹 ⊆ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ) ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ ( 𝐵 ∩ 𝐶 ) ) ) |
7 |
|
df-f |
⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) ) |
8 |
7
|
anbi1i |
⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ) |
9 |
|
anass |
⊢ ( ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ 𝐵 ) ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ ( 𝐹 Fn 𝐴 ∧ ( ran 𝐹 ⊆ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ) ) |
10 |
8 9
|
bitri |
⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ ( 𝐹 Fn 𝐴 ∧ ( ran 𝐹 ⊆ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ) ) |
11 |
|
df-f |
⊢ ( 𝐹 : 𝐴 ⟶ ( 𝐵 ∩ 𝐶 ) ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ ( 𝐵 ∩ 𝐶 ) ) ) |
12 |
6 10 11
|
3bitr4i |
⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ 𝐹 : 𝐴 ⟶ ( 𝐵 ∩ 𝐶 ) ) |
13 |
|
feq3 |
⊢ ( 𝐷 = ( 𝐵 ∩ 𝐶 ) → ( 𝐹 : 𝐴 ⟶ 𝐷 ↔ 𝐹 : 𝐴 ⟶ ( 𝐵 ∩ 𝐶 ) ) ) |
14 |
12 13
|
bitr4id |
⊢ ( 𝐷 = ( 𝐵 ∩ 𝐶 ) → ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ ( 𝐹 “ 𝐴 ) ⊆ 𝐶 ) ↔ 𝐹 : 𝐴 ⟶ 𝐷 ) ) |