Metamath Proof Explorer


Theorem lcd0

Description: The zero scalar of the closed kernel dual of a vector space. (Contributed by NM, 20-Mar-2015)

Ref Expression
Hypotheses lcd0.h 𝐻 = ( LHyp ‘ 𝐾 )
lcd0.u 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
lcd0.f 𝐹 = ( Scalar ‘ 𝑈 )
lcd0.z 0 = ( 0g𝐹 )
lcd0.c 𝐶 = ( ( LCDual ‘ 𝐾 ) ‘ 𝑊 )
lcd0.s 𝑆 = ( Scalar ‘ 𝐶 )
lcd0.o 𝑂 = ( 0g𝑆 )
lcd0.k ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊𝐻 ) )
Assertion lcd0 ( 𝜑𝑂 = 0 )

Proof

Step Hyp Ref Expression
1 lcd0.h 𝐻 = ( LHyp ‘ 𝐾 )
2 lcd0.u 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
3 lcd0.f 𝐹 = ( Scalar ‘ 𝑈 )
4 lcd0.z 0 = ( 0g𝐹 )
5 lcd0.c 𝐶 = ( ( LCDual ‘ 𝐾 ) ‘ 𝑊 )
6 lcd0.s 𝑆 = ( Scalar ‘ 𝐶 )
7 lcd0.o 𝑂 = ( 0g𝑆 )
8 lcd0.k ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊𝐻 ) )
9 eqid ( oppr𝐹 ) = ( oppr𝐹 )
10 1 2 3 9 5 6 8 lcdsca ( 𝜑𝑆 = ( oppr𝐹 ) )
11 10 fveq2d ( 𝜑 → ( 0g𝑆 ) = ( 0g ‘ ( oppr𝐹 ) ) )
12 9 4 oppr0 0 = ( 0g ‘ ( oppr𝐹 ) )
13 11 7 12 3eqtr4g ( 𝜑𝑂 = 0 )