Metamath Proof Explorer


Theorem lcd0

Description: The zero scalar of the closed kernel dual of a vector space. (Contributed by NM, 20-Mar-2015)

Ref Expression
Hypotheses lcd0.h ⊢ H = LHyp ⁡ K
lcd0.u ⊢ U = DVecH ⁡ K ⁡ W
lcd0.f ⊢ F = Scalar ⁡ U
lcd0.z ⊢ 0 ˙ = 0 F
lcd0.c ⊢ C = LCDual ⁡ K ⁡ W
lcd0.s ⊢ S = Scalar ⁡ C
lcd0.o ⊢ O = 0 S
lcd0.k ⊢ φ → K ∈ HL ∧ W ∈ H
Assertion lcd0 ⊢ φ → O = 0 ˙

Proof

Step Hyp Ref Expression
1 lcd0.h ⊢ H = LHyp ⁡ K
2 lcd0.u ⊢ U = DVecH ⁡ K ⁡ W
3 lcd0.f ⊢ F = Scalar ⁡ U
4 lcd0.z ⊢ 0 ˙ = 0 F
5 lcd0.c ⊢ C = LCDual ⁡ K ⁡ W
6 lcd0.s ⊢ S = Scalar ⁡ C
7 lcd0.o ⊢ O = 0 S
8 lcd0.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 eqid ⊢ opp r ⁡ F = opp r ⁡ F
10 1 2 3 9 5 6 8 lcdsca ⊢ φ → S = opp r ⁡ F
11 10 fveq2d ⊢ φ → 0 S = 0 opp r ⁡ F
12 9 4 oppr0 ⊢ 0 ˙ = 0 opp r ⁡ F
13 11 7 12 3eqtr4g ⊢ φ → O = 0 ˙