Metamath Proof Explorer


Theorem lcd0

Description: The zero scalar of the closed kernel dual of a vector space. (Contributed by NM, 20-Mar-2015)

Ref Expression
Hypotheses lcd0.h
|- H = ( LHyp ` K )
lcd0.u
|- U = ( ( DVecH ` K ) ` W )
lcd0.f
|- F = ( Scalar ` U )
lcd0.z
|- .0. = ( 0g ` F )
lcd0.c
|- C = ( ( LCDual ` K ) ` W )
lcd0.s
|- S = ( Scalar ` C )
lcd0.o
|- O = ( 0g ` S )
lcd0.k
|- ( ph -> ( K e. HL /\ W e. H ) )
Assertion lcd0
|- ( ph -> O = .0. )

Proof

Step Hyp Ref Expression
1 lcd0.h
 |-  H = ( LHyp ` K )
2 lcd0.u
 |-  U = ( ( DVecH ` K ) ` W )
3 lcd0.f
 |-  F = ( Scalar ` U )
4 lcd0.z
 |-  .0. = ( 0g ` F )
5 lcd0.c
 |-  C = ( ( LCDual ` K ) ` W )
6 lcd0.s
 |-  S = ( Scalar ` C )
7 lcd0.o
 |-  O = ( 0g ` S )
8 lcd0.k
 |-  ( ph -> ( K e. HL /\ W e. H ) )
9 eqid
 |-  ( oppR ` F ) = ( oppR ` F )
10 1 2 3 9 5 6 8 lcdsca
 |-  ( ph -> S = ( oppR ` F ) )
11 10 fveq2d
 |-  ( ph -> ( 0g ` S ) = ( 0g ` ( oppR ` F ) ) )
12 9 4 oppr0
 |-  .0. = ( 0g ` ( oppR ` F ) )
13 11 7 12 3eqtr4g
 |-  ( ph -> O = .0. )