Metamath Proof Explorer


Theorem lkrcl

Description: A member of the kernel of a functional is a vector. (Contributed by NM, 16-Apr-2014)

Ref Expression
Hypotheses lkrcl.v ⊢ 𝑉 = ( Base ‘ 𝑊 )
lkrcl.f ⊢ 𝐹 = ( LFnl ‘ 𝑊 )
lkrcl.k ⊢ 𝐾 = ( LKer ‘ 𝑊 )
Assertion lkrcl ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → 𝑋 ∈ 𝑉 )

Proof

Step Hyp Ref Expression
1 lkrcl.v ⊢ 𝑉 = ( Base ‘ 𝑊 )
2 lkrcl.f ⊢ 𝐹 = ( LFnl ‘ 𝑊 )
3 lkrcl.k ⊢ 𝐾 = ( LKer ‘ 𝑊 )
4 eqid ⊢ ( Scalar ‘ 𝑊 ) = ( Scalar ‘ 𝑊 )
5 eqid ⊢ ( 0g ‘ ( Scalar ‘ 𝑊 ) ) = ( 0g ‘ ( Scalar ‘ 𝑊 ) )
6 1 4 5 2 3 ellkr ⊢ ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ) → ( 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ↔ ( 𝑋 ∈ 𝑉 ∧ ( 𝐺 ‘ 𝑋 ) = ( 0g ‘ ( Scalar ‘ 𝑊 ) ) ) ) )
7 6 simprbda ⊢ ( ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ) ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → 𝑋 ∈ 𝑉 )
8 7 3impa ⊢ ( ( 𝑊 ∈ 𝑌 ∧ 𝐺 ∈ 𝐹 ∧ 𝑋 ∈ ( 𝐾 ‘ 𝐺 ) ) → 𝑋 ∈ 𝑉 )