Metamath Proof Explorer


Theorem mbfdm2

Description: The domain of a measurable function is measurable. (Contributed by Mario Carneiro, 31-Aug-2014)

Ref Expression
Hypotheses mbfmptcl.1 ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ MblFn )
mbfmptcl.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ 𝑉 )
Assertion mbfdm2 ( 𝜑 → 𝐴 ∈ dom vol )

Proof

Step Hyp Ref Expression
1 mbfmptcl.1 ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ MblFn )
2 mbfmptcl.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ 𝑉 )
3 2 ralrimiva ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 𝐵 ∈ 𝑉 )
4 dmmptg ⊢ ( ∀ 𝑥 ∈ 𝐴 𝐵 ∈ 𝑉 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = 𝐴 )
5 3 4 syl ⊢ ( 𝜑 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = 𝐴 )
6 mbfdm ⊢ ( ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ MblFn → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ dom vol )
7 1 6 syl ⊢ ( 𝜑 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ dom vol )
8 5 7 eqeltrrd ⊢ ( 𝜑 → 𝐴 ∈ dom vol )