Metamath Proof Explorer


Theorem mndtcob

Description: Lemma for mndtchom and mndtcco . (Contributed by Zhi Wang, 22-Sep-2024) (New usage is discouraged.)

Ref Expression
Hypotheses mndtcbaseu.c ⊢ ( 𝜑 → 𝐶 = ( MndToCat ‘ 𝑀 ) )
mndtcbaseu.m ⊢ ( 𝜑 → 𝑀 ∈ Mnd )
mndtcbaseu.b ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐶 ) )
mndtchom.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
Assertion mndtcob ( 𝜑 → 𝑋 = 𝑀 )

Proof

Step Hyp Ref Expression
1 mndtcbaseu.c ⊢ ( 𝜑 → 𝐶 = ( MndToCat ‘ 𝑀 ) )
2 mndtcbaseu.m ⊢ ( 𝜑 → 𝑀 ∈ Mnd )
3 mndtcbaseu.b ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐶 ) )
4 mndtchom.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
5 1 2 3 mndtcbasval ⊢ ( 𝜑 → 𝐵 = { 𝑀 } )
6 4 5 eleqtrd ⊢ ( 𝜑 → 𝑋 ∈ { 𝑀 } )
7 elsng ⊢ ( 𝑋 ∈ 𝐵 → ( 𝑋 ∈ { 𝑀 } ↔ 𝑋 = 𝑀 ) )
8 4 7 syl ⊢ ( 𝜑 → ( 𝑋 ∈ { 𝑀 } ↔ 𝑋 = 𝑀 ) )
9 6 8 mpbid ⊢ ( 𝜑 → 𝑋 = 𝑀 )