Metamath Proof Explorer


Theorem mndtcob

Description: Lemma for mndtchom and mndtcco . (Contributed by Zhi Wang, 22-Sep-2024) (New usage is discouraged.)

Ref Expression
Hypotheses mndtcbaseu.c ⊢ φ → C = MndToCat ⁡ M
mndtcbaseu.m ⊢ φ → M ∈ Mnd
mndtcbaseu.b ⊢ φ → B = Base C
mndtchom.x ⊢ φ → X ∈ B
Assertion mndtcob ⊢ φ → X = M

Proof

Step Hyp Ref Expression
1 mndtcbaseu.c ⊢ φ → C = MndToCat ⁡ M
2 mndtcbaseu.m ⊢ φ → M ∈ Mnd
3 mndtcbaseu.b ⊢ φ → B = Base C
4 mndtchom.x ⊢ φ → X ∈ B
5 1 2 3 mndtcbasval ⊢ φ → B = M
6 4 5 eleqtrd ⊢ φ → X ∈ M
7 elsng ⊢ X ∈ B → X ∈ M ↔ X = M
8 4 7 syl ⊢ φ → X ∈ M ↔ X = M
9 6 8 mpbid ⊢ φ → X = M