Metamath Proof Explorer


Theorem msrrcl

Description: If X and Y have the same reduct, then one is a pre-statement iff the other is. (Contributed by Mario Carneiro, 18-Jul-2016)

Ref Expression
Hypotheses mpstssv.p ⊢ 𝑃 = ( mPreSt ‘ 𝑇 )
msrf.r ⊢ 𝑅 = ( mStRed ‘ 𝑇 )
Assertion msrrcl ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( 𝑋 ∈ 𝑃 ↔ 𝑌 ∈ 𝑃 ) )

Proof

Step Hyp Ref Expression
1 mpstssv.p ⊢ 𝑃 = ( mPreSt ‘ 𝑇 )
2 msrf.r ⊢ 𝑅 = ( mStRed ‘ 𝑇 )
3 1 2 msrf ⊢ 𝑅 : 𝑃 ⟶ 𝑃
4 3 ffvelcdmi ⊢ ( 𝑋 ∈ 𝑃 → ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 )
5 4 a1i ⊢ ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( 𝑋 ∈ 𝑃 → ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) )
6 3 ffvelcdmi ⊢ ( 𝑌 ∈ 𝑃 → ( 𝑅 ‘ 𝑌 ) ∈ 𝑃 )
7 eleq1 ⊢ ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ↔ ( 𝑅 ‘ 𝑌 ) ∈ 𝑃 ) )
8 6 7 imbitrrid ⊢ ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( 𝑌 ∈ 𝑃 → ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) )
9 3 fdmi ⊢ dom 𝑅 = 𝑃
10 0nelxp ⊢ ¬ ∅ ∈ ( ( V × V ) × V )
11 1 mpstssv ⊢ 𝑃 ⊆ ( ( V × V ) × V )
12 11 sseli ⊢ ( ∅ ∈ 𝑃 → ∅ ∈ ( ( V × V ) × V ) )
13 10 12 mto ⊢ ¬ ∅ ∈ 𝑃
14 9 13 ndmfvrcl ⊢ ( ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 → 𝑋 ∈ 𝑃 )
15 14 adantl ⊢ ( ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) ∧ ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) → 𝑋 ∈ 𝑃 )
16 7 biimpa ⊢ ( ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) ∧ ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) → ( 𝑅 ‘ 𝑌 ) ∈ 𝑃 )
17 9 13 ndmfvrcl ⊢ ( ( 𝑅 ‘ 𝑌 ) ∈ 𝑃 → 𝑌 ∈ 𝑃 )
18 16 17 syl ⊢ ( ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) ∧ ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) → 𝑌 ∈ 𝑃 )
19 15 18 2thd ⊢ ( ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) ∧ ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 ) → ( 𝑋 ∈ 𝑃 ↔ 𝑌 ∈ 𝑃 ) )
20 19 ex ⊢ ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( ( 𝑅 ‘ 𝑋 ) ∈ 𝑃 → ( 𝑋 ∈ 𝑃 ↔ 𝑌 ∈ 𝑃 ) ) )
21 5 8 20 pm5.21ndd ⊢ ( ( 𝑅 ‘ 𝑋 ) = ( 𝑅 ‘ 𝑌 ) → ( 𝑋 ∈ 𝑃 ↔ 𝑌 ∈ 𝑃 ) )