Metamath Proof Explorer


Theorem msrrcl

Description: If X and Y have the same reduct, then one is a pre-statement iff the other is. (Contributed by Mario Carneiro, 18-Jul-2016)

Ref Expression
Hypotheses mpstssv.p ⊢ P = mPreSt ⁡ T
msrf.r ⊢ R = mStRed ⁡ T
Assertion msrrcl ⊢ R ⁡ X = R ⁡ Y → X ∈ P ↔ Y ∈ P

Proof

Step Hyp Ref Expression
1 mpstssv.p ⊢ P = mPreSt ⁡ T
2 msrf.r ⊢ R = mStRed ⁡ T
3 1 2 msrf ⊢ R : P ⟶ P
4 3 ffvelcdmi ⊢ X ∈ P → R ⁡ X ∈ P
5 4 a1i ⊢ R ⁡ X = R ⁡ Y → X ∈ P → R ⁡ X ∈ P
6 3 ffvelcdmi ⊢ Y ∈ P → R ⁡ Y ∈ P
7 eleq1 ⊢ R ⁡ X = R ⁡ Y → R ⁡ X ∈ P ↔ R ⁡ Y ∈ P
8 6 7 imbitrrid ⊢ R ⁡ X = R ⁡ Y → Y ∈ P → R ⁡ X ∈ P
9 3 fdmi ⊢ dom ⁡ R = P
10 0nelxp ⊢ ¬ ∅ ∈ V × V × V
11 1 mpstssv ⊢ P ⊆ V × V × V
12 11 sseli ⊢ ∅ ∈ P → ∅ ∈ V × V × V
13 10 12 mto ⊢ ¬ ∅ ∈ P
14 9 13 ndmfvrcl ⊢ R ⁡ X ∈ P → X ∈ P
15 14 adantl ⊢ R ⁡ X = R ⁡ Y ∧ R ⁡ X ∈ P → X ∈ P
16 7 biimpa ⊢ R ⁡ X = R ⁡ Y ∧ R ⁡ X ∈ P → R ⁡ Y ∈ P
17 9 13 ndmfvrcl ⊢ R ⁡ Y ∈ P → Y ∈ P
18 16 17 syl ⊢ R ⁡ X = R ⁡ Y ∧ R ⁡ X ∈ P → Y ∈ P
19 15 18 2thd ⊢ R ⁡ X = R ⁡ Y ∧ R ⁡ X ∈ P → X ∈ P ↔ Y ∈ P
20 19 ex ⊢ R ⁡ X = R ⁡ Y → R ⁡ X ∈ P → X ∈ P ↔ Y ∈ P
21 5 8 20 pm5.21ndd ⊢ R ⁡ X = R ⁡ Y → X ∈ P ↔ Y ∈ P