Metamath Proof Explorer


Theorem n0el2

Description: Two ways of expressing that the empty set is not an element of a class. (Contributed by Peter Mazsa, 31-Jan-2018)

Ref Expression
Assertion n0el2 ( ¬ ∅ ∈ 𝐴 ↔ dom ( ◡ E ↾ 𝐴 ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 dmopab3 ⊢ ( ∀ 𝑥 ∈ 𝐴 ∃ 𝑦 𝑦 ∈ 𝑥 ↔ dom { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝑥 ) } = 𝐴 )
2 n0el ⊢ ( ¬ ∅ ∈ 𝐴 ↔ ∀ 𝑥 ∈ 𝐴 ∃ 𝑦 𝑦 ∈ 𝑥 )
3 cnvepres ⊢ ( ◡ E ↾ 𝐴 ) = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝑥 ) }
4 3 dmeqi ⊢ dom ( ◡ E ↾ 𝐴 ) = dom { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝑥 ) }
5 4 eqeq1i ⊢ ( dom ( ◡ E ↾ 𝐴 ) = 𝐴 ↔ dom { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝑥 ) } = 𝐴 )
6 1 2 5 3bitr4i ⊢ ( ¬ ∅ ∈ 𝐴 ↔ dom ( ◡ E ↾ 𝐴 ) = 𝐴 )