Metamath Proof Explorer


Theorem nanim

Description: Implication in terms of alternative denial. (Contributed by Jeff Hoffman, 19-Nov-2007)

Ref Expression
Assertion nanim ( ( 𝜑 → 𝜓 ) ↔ ( 𝜑 ⊼ ( 𝜓 ⊼ 𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 nannan ⊢ ( ( 𝜑 ⊼ ( 𝜓 ⊼ 𝜓 ) ) ↔ ( 𝜑 → ( 𝜓 ∧ 𝜓 ) ) )
2 anidmdbi ⊢ ( ( 𝜑 → ( 𝜓 ∧ 𝜓 ) ) ↔ ( 𝜑 → 𝜓 ) )
3 1 2 bitr2i ⊢ ( ( 𝜑 → 𝜓 ) ↔ ( 𝜑 ⊼ ( 𝜓 ⊼ 𝜓 ) ) )