Metamath Proof Explorer


Theorem nelsubc

Description: An empty "hom-set" for non-empty base satisfies all conditions for a subcategory but the existence of identity morphisms. (Contributed by Zhi Wang, 5-Nov-2025)

Ref Expression
Hypotheses nelsubc.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
nelsubc.s ⊢ ( 𝜑 → 𝑆 ⊆ 𝐵 )
nelsubc.0 ⊢ ( 𝜑 → 𝑆 ≠ ∅ )
nelsubc.j ⊢ ( 𝜑 → 𝐽 = ( ( 𝑆 × 𝑆 ) × { ∅ } ) )
nelsubc.h ⊢ 𝐻 = ( Homf ‘ 𝐶 )
nelsubc.i ⊢ 1 = ( Id ‘ 𝐶 )
nelsubc.o ⊢ · = ( comp ‘ 𝐶 )
Assertion nelsubc ( 𝜑 → ( 𝐽 Fn ( 𝑆 × 𝑆 ) ∧ ( 𝐽 ⊆cat 𝐻 ∧ ( ¬ ∀ 𝑥 ∈ 𝑆 ( 1 ‘ 𝑥 ) ∈ ( 𝑥 𝐽 𝑥 ) ∧ ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑆 ∀ 𝑧 ∈ 𝑆 ∀ 𝑓 ∈ ( 𝑥 𝐽 𝑦 ) ∀ 𝑔 ∈ ( 𝑦 𝐽 𝑧 ) ( 𝑔 ( ⟨ 𝑥 , 𝑦 ⟩ · 𝑧 ) 𝑓 ) ∈ ( 𝑥 𝐽 𝑧 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 nelsubc.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
2 nelsubc.s ⊢ ( 𝜑 → 𝑆 ⊆ 𝐵 )
3 nelsubc.0 ⊢ ( 𝜑 → 𝑆 ≠ ∅ )
4 nelsubc.j ⊢ ( 𝜑 → 𝐽 = ( ( 𝑆 × 𝑆 ) × { ∅ } ) )
5 nelsubc.h ⊢ 𝐻 = ( Homf ‘ 𝐶 )
6 nelsubc.i ⊢ 1 = ( Id ‘ 𝐶 )
7 nelsubc.o ⊢ · = ( comp ‘ 𝐶 )
8 1 2 3 4 5 nelsubclem ⊢ ( 𝜑 → ( 𝐽 Fn ( 𝑆 × 𝑆 ) ∧ ( 𝐽 ⊆cat 𝐻 ∧ ( ¬ ∀ 𝑥 ∈ 𝑆 ( 1 ‘ 𝑥 ) ∈ ( 𝑥 𝐽 𝑥 ) ∧ ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑆 ∀ 𝑧 ∈ 𝑆 ∀ 𝑓 ∈ ( 𝑥 𝐽 𝑦 ) ∀ 𝑔 ∈ ( 𝑦 𝐽 𝑧 ) ( 𝑔 ( ⟨ 𝑥 , 𝑦 ⟩ · 𝑧 ) 𝑓 ) ∈ ( 𝑥 𝐽 𝑧 ) ) ) ) )