Metamath Proof Explorer


Theorem nn0mulfsum

Description: Trivial algorithm to calculate the product of two nonnegative integers a and b by adding b to itself a times. (Contributed by AV, 17-May-2020)

Ref Expression
Assertion nn0mulfsum ( ( 𝐴 ∈ ℕ0 ∧ 𝐵 ∈ ℕ0 ) → ( 𝐴 · 𝐵 ) = Σ 𝑘 ∈ ( 1 ... 𝐴 ) 𝐵 )

Proof

Step Hyp Ref Expression
1 fzfid ⊢ ( 𝐴 ∈ ℕ0 → ( 1 ... 𝐴 ) ∈ Fin )
2 nn0cn ⊢ ( 𝐵 ∈ ℕ0 → 𝐵 ∈ ℂ )
3 fsumconst ⊢ ( ( ( 1 ... 𝐴 ) ∈ Fin ∧ 𝐵 ∈ ℂ ) → Σ 𝑘 ∈ ( 1 ... 𝐴 ) 𝐵 = ( ( ♯ ‘ ( 1 ... 𝐴 ) ) · 𝐵 ) )
4 1 2 3 syl2an ⊢ ( ( 𝐴 ∈ ℕ0 ∧ 𝐵 ∈ ℕ0 ) → Σ 𝑘 ∈ ( 1 ... 𝐴 ) 𝐵 = ( ( ♯ ‘ ( 1 ... 𝐴 ) ) · 𝐵 ) )
5 hashfz1 ⊢ ( 𝐴 ∈ ℕ0 → ( ♯ ‘ ( 1 ... 𝐴 ) ) = 𝐴 )
6 5 adantr ⊢ ( ( 𝐴 ∈ ℕ0 ∧ 𝐵 ∈ ℕ0 ) → ( ♯ ‘ ( 1 ... 𝐴 ) ) = 𝐴 )
7 6 oveq1d ⊢ ( ( 𝐴 ∈ ℕ0 ∧ 𝐵 ∈ ℕ0 ) → ( ( ♯ ‘ ( 1 ... 𝐴 ) ) · 𝐵 ) = ( 𝐴 · 𝐵 ) )
8 4 7 eqtr2d ⊢ ( ( 𝐴 ∈ ℕ0 ∧ 𝐵 ∈ ℕ0 ) → ( 𝐴 · 𝐵 ) = Σ 𝑘 ∈ ( 1 ... 𝐴 ) 𝐵 )