Metamath Proof Explorer


Theorem nnaddscl

Description: The positive surreal integers are closed under addition. (Contributed by Scott Fenton, 15-Apr-2025)

Ref Expression
Assertion nnaddscl ( ( 𝐴 ∈ ℕs𝐵 ∈ ℕs ) → ( 𝐴 +s 𝐵 ) ∈ ℕs )

Proof

Step Hyp Ref Expression
1 n0addscl ( ( 𝐴 ∈ ℕ0s𝐵 ∈ ℕ0s ) → ( 𝐴 +s 𝐵 ) ∈ ℕ0s )
2 1 ad2ant2r ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → ( 𝐴 +s 𝐵 ) ∈ ℕ0s )
3 simpll ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 𝐴 ∈ ℕ0s )
4 3 n0snod ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 𝐴 No )
5 simprl ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 𝐵 ∈ ℕ0s )
6 5 n0snod ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 𝐵 No )
7 simplr ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 0s <s 𝐴 )
8 simprr ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 0s <s 𝐵 )
9 4 6 7 8 addsgt0d ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → 0s <s ( 𝐴 +s 𝐵 ) )
10 2 9 jca ( ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) → ( ( 𝐴 +s 𝐵 ) ∈ ℕ0s ∧ 0s <s ( 𝐴 +s 𝐵 ) ) )
11 elnns2 ( 𝐴 ∈ ℕs ↔ ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) )
12 elnns2 ( 𝐵 ∈ ℕs ↔ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) )
13 11 12 anbi12i ( ( 𝐴 ∈ ℕs𝐵 ∈ ℕs ) ↔ ( ( 𝐴 ∈ ℕ0s ∧ 0s <s 𝐴 ) ∧ ( 𝐵 ∈ ℕ0s ∧ 0s <s 𝐵 ) ) )
14 elnns2 ( ( 𝐴 +s 𝐵 ) ∈ ℕs ↔ ( ( 𝐴 +s 𝐵 ) ∈ ℕ0s ∧ 0s <s ( 𝐴 +s 𝐵 ) ) )
15 10 13 14 3imtr4i ( ( 𝐴 ∈ ℕs𝐵 ∈ ℕs ) → ( 𝐴 +s 𝐵 ) ∈ ℕs )