Metamath Proof Explorer


Theorem opelopabb

Description: Membership of an ordered pair in a class abstraction of ordered pairs, biconditional form. (Contributed by BJ, 17-Dec-2023)

Ref Expression
Hypotheses opelopabb.xph ⊢ ( 𝜑 → ∀ 𝑥 𝜑 )
opelopabb.yph ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
opelopabb.xch ⊢ ( 𝜑 → Ⅎ 𝑥 𝜒 )
opelopabb.ych ⊢ ( 𝜑 → Ⅎ 𝑦 𝜒 )
opelopabb.is ⊢ ( ( 𝜑 ∧ ( 𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ) ) → ( 𝜓 ↔ 𝜒 ) )
Assertion opelopabb ( 𝜑 → ( ⟨ 𝐴 , 𝐵 ⟩ ∈ { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝜓 } ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ 𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 opelopabb.xph ⊢ ( 𝜑 → ∀ 𝑥 𝜑 )
2 opelopabb.yph ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
3 opelopabb.xch ⊢ ( 𝜑 → Ⅎ 𝑥 𝜒 )
4 opelopabb.ych ⊢ ( 𝜑 → Ⅎ 𝑦 𝜒 )
5 opelopabb.is ⊢ ( ( 𝜑 ∧ ( 𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ) ) → ( 𝜓 ↔ 𝜒 ) )
6 elopab ⊢ ( ⟨ 𝐴 , 𝐵 ⟩ ∈ { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝜓 } ↔ ∃ 𝑥 ∃ 𝑦 ( ⟨ 𝐴 , 𝐵 ⟩ = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) )
7 1 2 3 4 5 copsex2b ⊢ ( 𝜑 → ( ∃ 𝑥 ∃ 𝑦 ( ⟨ 𝐴 , 𝐵 ⟩ = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ 𝜒 ) ) )
8 6 7 bitrid ⊢ ( 𝜑 → ( ⟨ 𝐴 , 𝐵 ⟩ ∈ { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝜓 } ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ 𝜒 ) ) )