Metamath Proof Explorer


Theorem opnlen0

Description: An element not less than another is nonzero. TODO: Look for uses of necon3bd and op0le to see if this is useful elsewhere. (Contributed by NM, 5-May-2013)

Ref Expression
Hypotheses op0le.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
op0le.l ⊢ ≤ = ( le ‘ 𝐾 )
op0le.z ⊢ 0 = ( 0. ‘ 𝐾 )
Assertion opnlen0 ( ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ ¬ 𝑋 ≤ 𝑌 ) → 𝑋 ≠ 0 )

Proof

Step Hyp Ref Expression
1 op0le.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 op0le.l ⊢ ≤ = ( le ‘ 𝐾 )
3 op0le.z ⊢ 0 = ( 0. ‘ 𝐾 )
4 1 2 3 op0le ⊢ ( ( 𝐾 ∈ OP ∧ 𝑌 ∈ 𝐵 ) → 0 ≤ 𝑌 )
5 4 3adant2 ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → 0 ≤ 𝑌 )
6 breq1 ⊢ ( 𝑋 = 0 → ( 𝑋 ≤ 𝑌 ↔ 0 ≤ 𝑌 ) )
7 5 6 syl5ibrcom ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( 𝑋 = 0 → 𝑋 ≤ 𝑌 ) )
8 7 necon3bd ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( ¬ 𝑋 ≤ 𝑌 → 𝑋 ≠ 0 ) )
9 8 imp ⊢ ( ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ ¬ 𝑋 ≤ 𝑌 ) → 𝑋 ≠ 0 )